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(2x-5)/(8x^2-2x-3)=0
Domain of the equation: (8x^2-2x-3)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
8x^2-2x!=3
x∈R
(2x-5)=0
We get rid of parentheses
2x-5=0
We move all terms containing x to the left, all other terms to the right
2x=5
x=5/2
x=2+1/2
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